, 14.10.2019 13:30, kiryakuantseva

Вопрос/Задача:

# :на тело объёмом 5 дм в кубе при полном погружении в жидкость действует выталкивающая сила 50 ньютонов. какая это жидкость?

## Ответы на вопрос

Ответ разместил: Гость

а и б) найдем i. i=n/u=40/120=0,3. r=u/i=120/0.3=40 ом.

Ответ разместил: Гость

уравнение состояния идеального газа:

pv = (m/m)rt.

после хранения:

0,8pv = (m1/m)r0,8t.

отсюда m =m1(так как m = const по условию).

изохорический процесс ( масса не меняется, как и объем)

ответ: количество газа в не изменилось.

Ответ разместил: Гость
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Ответ разместил: Criss666

v=5дм3=0,005м3

fa=pgv

p=fa/gv

p=50: (10*0,005)=1000кг/м3

вода

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