Физика
Физика, 09.09.2019 15:45, lizabelova00

Вопрос/Задача:

Дуговая печь потребляет ток 200 а от сети с напряжением 120 в через ограничиваюшее сопративление 0,2 ом. найти мощьность потребляемую печью? ?

Ответы на вопрос

Ответ
Ответ разместил: Гость
Simple present, present continuous past, or past continuous. part 1: situation: right now tommy (is sitting) at the desk. he (is writ ing) in his grammar workbook. his roommate, bert, (is sitt ing) at his desk, but he (is not study ing) he (is star ing) out the window. tommy ( to know what bert (is look ing) at. here is the dialogue: t: bert, what (are you look ing) at? b: i (am watch ing) the bicyclists. they are very skillful. i (do not know) how to ride a bike, so i (admire) anyone who can. come over to the window. look at that guy in the blue shirt. he (is steer ing) his bike with one hand while he (is drink ing) a coke with his other. and all the while, he (is weav ing) in and out of the heavy street traffic and the pedestrian traffic. he (seems) fearless. t: riding a bike (is not) as hard as it (looks) .. i'll teach you to ride a bicycle if you'd like. b: really? great. t: how come you don't know how to ride a bike? b: i never (had) a bike when i (was) a kid. my family (was) too poor. one time i (tried) to learn on the bike of one of my friends, but the other kids (laughed) at me. i never (tried) again because i (was) too embarrassed. but i'd love to learn now! when can we start? part 2 yesterday tommy (was sitt ing) at his desk and (writ ing) his grammar workbook. his roommate, bert, (was sitt at his desk, but he (was not study ing) he (was star ing) out the window. he (was watch ing) bicyclists on the street below. tommy (walked) over to the window. bert (pointed) out one bicyclist in particular. this bicyclist (was steer ing) with one hand while he (was drink ing) a with the other. and all the while, he (was weav ing) in and out of the heavy traffic. bert never (leart) how to ride a bike cyclist ( fearless. when he ( a kid, so tommy (offered) to teach him how. bert (accepted)
Ответ
Ответ разместил: Гость

на нагрев воды от 0 до 100 градусов требуется q1=cm(t2-t1)=0,1*4200*(100-10)=37800 дж

на испарение воды затратилось 200000-37800=162200 дж

тогда испарилось воды m=q/r=162200/2*10⁶=0,081 кг≈  81 г

Ответ
Ответ разместил: Гость

рис.1 r=r1+r2+r3=6 ом

рис.2 r=r1*r2*r3/(r2r3+r1r3+r1r2)=6/11 ом

рис.3 r= r1+r2r3/r2+r3=2.5 ом

 

Ответ
Ответ разместил: anuaraminov10ozppq2

r=0,2 ом. падение напряжения на : ir = 200*0,2 = 40 в.

тогда напряжение на печи:

u = v - ir = 120 - 40 = 80 в.

потребляемая мощность:

p = u*i = 80*200 = 16 квт

ответ: 16 квт.

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