Химия
Химия, 14.10.2019 11:40, т221

Вопрос/Задача:

Напишите уравнения реакций: взаимодействие хлора с железом, взаимодействие хлора с йодидом калия.
для каждой реакции составьте электронные уравнения процессов окисления и восстановления . укажите окислитель и восстановитель

Ответы на вопрос

Ответ
Ответ разместил: Гость

с + o2 = co2

n(co2) = n(c) = (900*0,8)/12 = 60 моль; 0.8 - это часть чистого угля

v(co2) = 60 моль * 22,4 л/моль = 1344 л

ответ - 1344 л

Ответ
Ответ разместил: Гость

mr(любого газа)=22,4 г/моль

v=mr*u=22,4*0,2=4,48 литра
Ответ
Ответ разместил: Гость

                73 г                                           х л

                73 г                                         22,4 л

1. сначала определим чистую массу кислоты в растворе:

  m(hcl)=m(раствора)*w(hcl)=200*0,365=73 г

2. из уравнения видим,что при взаимодействии 73 г кислоты выделяется 22,4 л вдорода 

Ответ
Ответ разместил: Гость

na2so4+bacl2=baso4+2nacl0.16=m/0.1m=1.6г(bacl2)n(bacl2)=1.6/208=0.0077мольm(na2so4)=0.0077*126=0.97гc=m/v0.5=0.97/vv=1.94л=1940мл

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